[algorithm] 옹알이

function solution(babbling) {
  const word = ['aya', 'ye', 'woo', 'ma']

  let count = 0

  const result = babbling.map(x => {
    word.map(y => (x = x.replace(y, '1')))
    if (!isNaN(x)) count = count + 1
  })

  return count
}